Matematika

Pertanyaan

( 1 + csc x ) ( 1 - sin x ) = cot x cos x
( 1 + csc x ) ( 1 - sin x ) = cot x cos x

1 Jawaban

  • ( 1 + csc x ) ( 1 - sin x ) = cot x . cos x
    [tex]( 1 + \frac{1}{sin x} ) ( 1 - sin x)[/tex]
    = cot x . cos x
    1 - sin x + [tex] \frac{1}{sin x}[/tex] - 1 = cot x. cos x
    [tex] \frac{1}{sin x}[/tex] - sin x = cot x . cos x
    [tex] \frac{1- sin^{2} x }{sin x} [/tex] = cot x. cos x
    [tex] \frac{ cos^{2} x}{sin x} [/tex] = cot x . cos x
    [tex] \frac{cos x}{sin x} [/tex] . cos x = cot x . cos x
    [tex] \frac{1}{tan x} [/tex] . cos x = cot x . cos x
    cot x . cos x = cot x . cos x

    atau
    ( 1 + csc x ) ( 1 - sin x ) = cot x . cos x
    ( 1 + csc x ) ( 1 - sin x ) = [tex] \frac{1}{tan x} [/tex] . cos x
    ( 1 + csc x ) ( 1 - sin x ) = [tex] \frac{cos x}{sin x} [/tex] . cos x
    ( 1 + csc x ) ( 1 - sin x ) = [tex] \frac{ cos^{2} x}{sin x} [/tex]
    ( 1 + csc x ) ( 1 - sin x ) = [tex] \frac{1- sin^{2} x }{sin x} [/tex]
    ( 1 + csc x ) ( 1 - sin x ) = [tex] \frac{1}{sin x}[/tex] - sin x
    ( 1 + csc x ) ( 1 - sin x ) = ( 1 + csc x ) ( 1 - sin x )

    semoga membantu :) jadikan yang terbaik ya :))