Matematika

Pertanyaan

Bantu jawab yang no 27 a-f dong
Bantu jawab yang no 27 a-f dong

1 Jawaban

  • a) Lp = 6s²
    = 6(8)²
    = 384 cm²
    V = s³
    = 512cm³
    b) Lp = 2(1/2 (6+3)4) + (5 x 12) + (4 x 12) + (6 x 12)
    = 36 + 60 + 48 + 72
    = 216cm²
    V = luas alas x tinggi
    =(6+3)4 / 2 x 12
    = 18 x 12
    = 216 cm³
    c) t segitiga = √13² - 5²
    = 12
    Lp = (10 x 10) + (4 x 1/2 x 10 x 12)
    = 100 + 240
    = 340 cm²
    tinggi limas = √12² - 5²
    = √119
    V = 1/3 x 10 x 10 x √119
    = 100√119/3 cm³
    d) Lp = 2(9 x 6) + 2(20x6) + 2(9x20)
    = 108 + 240 + 360
    = 708 cm²
    V = luas alas x tinggi
    = 6 x 9 x 20
    = 1080cm³
    e) Lp = 2(1/2(16+12)8) + ( 8 x 12) + (8 x 16) + (8 x 8) + (10 x 8)
    = 224 +96 + 128 + 64 + 80
    = 592 cm²
    V = Luas alas x tinggi
    = 1/2(16 +12)8 x 8
    = 112 x 8
    = 896 cm³
    f) Lp = ( 8x11) + (2 (8x5 + 4x3)) + (11x5) + (11x5) + (4x11) + (3x11) + (9x11)
    = 88 + 104+ 55 + 55 + 44 + 33 + 99
    = 478cm²
    V = Luas alas x tinggi
    = (8x5 + 4x3) x 11
    = 52 x 11
    = 572 cm³