1/16^x-1 kurangdarisamadengan akar 1/2^3x+7 Tlg... kasih cranya jga

[tex] \frac{1}{ 16^{x-1} } \leq \sqrt{ \frac{1}{ 2^{3x+7} } } \\ \\ \frac{1}{ 2^{4(x-1)} } \leq \sqrt{2^{-(3x+7)}} \\ \\ \frac{1}{2^{4x-4}} \leq \sqrt{2^{-3x-7}} \\ \\ 2^{-(4x-4)} \leq 2^{ \frac{1}{2} (-3x-7)} \\ \\ 2^{-4x+4} \leq 2^{- \frac{3}{2}x- \frac{7}{2} } \\ \\ -4x+4 \leq - \frac{3}{2}x- \frac{7}{2} \\ \\ -4x+(- \frac{3}{2}x )+4-4 \leq - \frac{3}{2}x+ \frac{3}{2}x- \frac{7}{2} -4 \\ \\ [/tex][tex]- \frac{11}{2}x \leq - \frac{15}{2} \\ \\ \frac{ -\frac{11}{2}x }{-\frac{11}{2}} \leq \frac{- \frac{15}{2} }{-\frac{11}{2}} \\ \\ x \geq \frac{30}{22} \\ \\ x \geq 1 \frac{8}{22} [/tex]

[tex]\displaystyle \left(\frac{1}{16}\right)^{x-1} \leq \sqrt \left(\frac{1}{2}\right)^{3x+7}} \\ \\ 16^{-(x-1)} \leq \sqrt{2^{-(3x+7)}} \\ 2^{-4(x-1)} \leq 2^{\frac{-(3x+7)}{2}} \\ -4(x-1) \leq \frac{-(3x+7)}{2} \\ -8(x-1) \leq -(3x+7) \\ 8(x-1) \geq 3x+7 \\ 8x-8 \geq 3x+7 \\ 5x \geq 15 \\ x \geq 3[/tex]