1. hitung konsentrasi oh- larutan nh4oh 0,05 m ( kb= 2x10'-5) 2. hitung konsentrasi h+ larutan ch3cooh 0,1 ( alpha = 0,04 )

1.
[OH-] = √kb . [NH4OH]
[OH-] = √2 x 10^-5 . 5 x 10^-2
[OH-] = √10 x 10^-7
[OH-] = √10-6
[OH-] = 10^-3
[OH-] = 0,001

2.
[H+] = [CH3COOH] . alpha
[H+] = 1 x 10^-1 x 4 x 10^-2
[H+] = 4 x 10^-3
[H+] = 0,004