Bagaimana cara mencari nilai minimun dan maksimum dlm soal no 2 mohn dibantu (:

a) minimum jk sin x = - 1 mk y min = 6(-1) = - 6
Maksimum jk sin x = 1 mk y maks = 6(1) = 6

b) minimum jk cos x = - 1 mk y min = - 1 - 2 = - 3
Maksimum jk cos x = 1 mk y maks = 1 - 2 = - 1