perbandingan panjang,lebar dan tinggi balok 4:3:2. jika luas permukaannya 468cm2,tentukanlah ukuran balok tersebut

Lp = 2(p × l) + 2(l × t) + 2(p × t).
468 = 2(4x × 3x) + 2(3x × 2x) + 2(4x × 2x).
468 = 2(12x⁲) + 2(6x⁲) + 2(8x⁲).
468 = 24x⁲ + 12x⁲ + 16x⁲.
468 = 52x⁲.

x⁲ = 468/52.
x⁲ = 9.
x = √9.
x = 3.

p = 4x = 4(3) = 12cm.
l = 3x = 3(3) = 9cm.
t = 2x = 2(3) = 6cm.

Ukuran balok
= p × l × t.
= 12cm × 9cm × 6cm.

L = 2(pxl + lxt + pxt)
468 = 2(4a x 3a + 3a x 2a + 4a x 2a)
468 = 2(12a² + 6a²+ 8a²)
468 = 52a²
468 : 52 = a²
9 = a²
3 = a

p = 4a => 4(3) = 12 cm
l = 3a => 3(3) = 9 cm
t = 2a => 2(3) = 6 cm

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