diketahui tan theta 12/5 theta berada di kuadran tiga.tentukan coses theta

Kuadran III, x dan y negatif
[tex]
Tan = \frac{y}{x} = \frac{12}{5} \\
y = -12 \\
x = -5 \\
r = \sqrt{12 ^{2} +5 ^{2} } \\
r = \sqrt{144+25} \\
r = \sqrt{169} \\
r = 13 \\
cosec = \frac{r}{y} = -\frac{13}{12}
[/tex]