tolong bantu jawab kak.. pakai jalannya ya kak

f(x) = 8 + 3x^2 - 3x^3 pada interval 1 ≤ x ≤ 4 => x = {1,2,3,4}
f(1) = 8 + 3(1)^2 - 3(1)^3 = 8 + 3 - 3 = 8
f(2) = 8 + 3(2)^2 - 3(2)^3 = 8 + 12 - 24 = -4
f(3) = 8 + 3(3)^2 - 3(3)^3 = 8 + 27 - 81 = -46
f(4) = 8 + 3(4)^2 - 3(4)^3 = 8 + 48 - 192 = -136
Jadi maksimumnya 8 dan minimumnya -136
(Tak ada jawaban)

Jika soalnya f(x) = 8 + 3x^2 - 3x^3 dan tidak ada internalnya maka
Jawabannya adalah:
f'(x) = 6x - 9x^2 = 0
=> 3x(2 - 3x) = 0
=> 3x = 0 => x = 0
=> (2 - 3x) = 0 => -3x = -2 => x = 2/3
f(0) = 8 + 3(0)^2 - 3(0)^3 = 8 + 0 - 0 = 8 => nilai minimum
f(2/3) = 8 + 3(2/3)^2 - 3(2/3)^3 = 8 + 12/9 - 8/9 = 8 4/9 => maksimum