diketahui permutasi n + 1 p4 ==6(np3) ,nilai n adalah

Permutasi

(n+1) P4 = 6. (nP3)
(n+1) ! /(n+1-4)!  = 6. [ n! / (n-3)! ]
(n+1)(n!) / (n-3)! = 6 (n) ! / (n-3)! ......*yng n!/(n-3)! di coret*
n+1 = 6
n = 5