lim x->1 akarx2+3-x-1 per 1-x2 =

Langsung aja y

lim √(x²+3) - x - 1 / 1 - x²
x→1

lim (√(x²+3)-(x-1) (√(x²+3)+(x-1) / (1-x²)(√(x²+3)+(x-1)
x→1

lim (x²+3 - x²+2x-1 / (1-x²)(√(x²+3)+(x-1)
x→1

= (1)²+3-(1)²+2(1)-1 / (1-(1)²)(√(1)²+3) + (1-1)

= 3+2-1 / (0) (2) + (0)

= 4 / 0

= 0

semoga berguna +_+