Ditentukan suatu fungsi f(x)=2/3(x+6).Jika domain dari fungsi tersebut [3,6,12,24], maka range fungsi trrsebut adslah...

f(3) = 2/3 (3+6)
      = 2/3 (9)
      = 6
f(6) = 2/3 (6+6)
       = 2/3 (12)
       = 8
f(12) = 2/3 (12+6)
        = 2/3 (18)
        = 12
f(24) = 2/3 (24+6)
         = 2/3 (30)
         = 20

Range = 6,8,12,20

f(x)=2/3(x+6)
f(3) = 2/3 (3+6) = 2/3 . 9 = 6
f(6) = 2/3 (12) = 8
f(12) = 2/3 (18) = 12
f(24) = 2/3 (30) = 20
maka range (6,8,12,20)