Tolong dijawab ya ^^

Rasional Bentuk Akar

(3 - √6)/ (3 + √6) =
=(3-√6)/(3+√6) x (3-√6)/(3-√6)
= (3-√6)²/ (3+√6)(3-√6)
= (9+6- 6√6)/ (9-6)
= (15 - 6√6)/(3)
=3 (5- 2√6)/ (3)
= 5 - 2√6