tolong dibantu bsk dikumpulin
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tolong dibantu bsk dikumpulin
1 Jawaban
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1. Jawaban Syarofuddin
a.KM=√52
1/2KM=√52:2= √13
t²=13²(-√13)²
=169-13
=156
t=√156
=2√39 cm
b. tΔ²=13²-3²=169-9=160
tΔ1=√160=4√10
tΔ²=13²-2²=169-4=165
tΔ2= √165 cm
Lp=LΔ+2LΔ1+2LΔ2
=(6 x 4)+ 2(1/2 x 6 x 4√10)+2(1/2 x 4 x √165)
=(24 + 24√10+4√165)cm²
c. LN=KM=√52=2√13cm
L= 1/2 x a x t= 1/2 x 2 √13 x 2 √39 =1/2 x 4 √507= 1/2 x 4 x 14√3 =28√3 cm
d. V= 1/3 La. tl
1/3. (6.4).(2√39)
=16√39 cm³