Matematika

Pertanyaan

tolong dibantu bsk dikumpulin
tolong dibantu bsk dikumpulin

1 Jawaban

  • a.KM=√52
      1/2KM=√52:2= √13

    t²=13²(-√13)²
      =169-13
      =156
    t=√156
      =2√39 cm

    b. tΔ²=13²-3²=169-9=160
    tΔ1=√160=4√10
    tΔ²=13²-2²=169-4=165
    tΔ2= √165 cm
    Lp=LΔ+2LΔ1+2LΔ2
    =(6 x 4)+ 2(1/2 x 6 x 4√10)+2(1/2 x 4 x √165)
    =(24 + 24√10+4√165)cm²

    c. LN=KM=√52=2√13cm
    L= 1/2 x a x t= 1/2 x 2 √13 x 2 √39 =1/2 x 4 √507= 1/2 x 4 x 14√3 =28√3 cm

    d. V= 1/3 La. tl
    1/3. (6.4).(2√39)
    =16√39 cm³