Matematika

Pertanyaan

jika titik-titik (2,7),(6,-1), dan (9,m) terletak dalam satu garis lurus, maka nilai m adalah...
a.3
b.2
c.-1
d.-7

1 Jawaban

  • A = (2,7)
    B = (6,-1)
    C = (9,m)

    AB = (6,-1) - (2,7) = (4,-8)
    BC = (9,m) - (6,-1) = (3,m + 1)

    AB = k × BC
    (4,-8) = k × (3,m + 1)
    (4,-8) = (3k, k(m + 1))
    4 = 3k
    4/3 = k

    k(m + 1) = -8
    4/3(m + 1) = -8
    4/3m + 4/3 = -8
    4/3m = -28/3
    m = -28/3 × 3/4
    m = -7 (D)

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