hitunglah luas segitiga PQR QR= 8cm, PR=8√3
Matematika
gita567
Pertanyaan
hitunglah luas segitiga PQR QR= 8cm, PR=8√3 <p= 30°
1 Jawaban
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1. Jawaban bapakdr
qr/sin p = pr/sin q
8/sin 30 = 8√3/sin q
8.sin q = 8√3.sin 30
8.sin q = 8√3 (1/2)
8.sin q = 4√3
sin q = 4√3 / 8
sin q = √3/2
q = 60
<r = 180 - <p - <q = 180-30-60 = 90
L = ½.QR.PR.sin R
L = ½(8)(8√3).sin 90
L = 4(8√3)(1)
L = 32√3