tolong bantu no 5....!!!!
Matematika
adelia689
Pertanyaan
tolong bantu no 5....!!!!
1 Jawaban
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1. Jawaban johannahelina
Luas ABCDE = Luas ABCD + Luas ADE
Luas ABCD:
½ × (a + b) × t
½ × (12 + 20) × 16
½ × 32 × 16 = 256 cm²
Luas ADE:
EF = √17² - 8²
EF = √289 - 64
EF = √225
EF = 15 cm = t
½ × a × t
½ × 16 × 15 = 120 cm²
Luas ABCDE = 256 + 120 = 376 cm² (B)