Matematika

Pertanyaan

tolong bantu no 5....!!!!
tolong bantu no 5....!!!!

1 Jawaban

  • Luas ABCDE = Luas ABCD + Luas ADE

    Luas ABCD:
    ½ × (a + b) × t
    ½ × (12 + 20) × 16
    ½ × 32 × 16 = 256 cm²

    Luas ADE:
    EF = √17² - 8²
    EF = √289 - 64
    EF = √225
    EF = 15 cm = t
    ½ × a × t
    ½ × 16 × 15 = 120 cm²

    Luas ABCDE = 256 + 120 = 376 cm² (B)