massa unsur nitrogen yang terkandung dalam 60 gram pupuk urea (CO(NH2)2) adalah................gram (Ar C=12,O=16,N=14,H=1)

(CO(NH₂)₂) = CON₂H₄

Mr CON₂H₄ = 1 × Ar C + 1 × Ar O + 2 × Ar N + 4 × Ar H
Mr CON₂H₄ = 1 × 12 + 1 × 16 + 2 × 14 + 4 × 1
Mr CON₂H₄ = 12 + 16 + 28 + 4
Mr CON₂H₄ = 60

m N : m CON₂H₄ = 14 : 60
m N = 14/60 × 60 gram
m N = 14 gram

Mr CO(NH2)2
= Ar C + Ar O + 2 x Ar N + 4 x Ar H
= 12 + 16 + 28 + 4
= 60

Massa Nitrogen
= Ar N2 / Mr CO(NH2)2 x 60
= 28 / 60 x 60
= 28 gram

Semoga membantu;)