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Pertanyaan

Sebanyak 600 ml larutan CH3COOH 0,1 M , Di campurka dengan 600 ml CH3COONa 0,15 M (ka CH3COOH = 1,8 × 10^-5). Tentukan PH campuran tsb

1 Jawaban

  • jumlah mol CH3COOH = M x V = 0,1 x 600 = 60 mmol
    jumlah mol CH3COOHNa = M x V = 0,15 x 600 = 90 mmol
    [H+] = ka x a/g
    = 1,8.10^-5 x 60/90
    = 1,2 . 10^-5
    PH = - log [H+]
    = - log 1,2.10^-5
    = 5 - log 1,2
    Semoga membantu;))

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