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Pertanyaan

Kelarutan magnesium oksalat,MgC2O4,dalam air sebesar 0,0093 mol L⁻¹. Hitunglah Ksp Magnesium oksalat itu.(Ar O =16; C =12; Mg = 24 )

1 Jawaban

  • s = 9,3 . 10^-3

    MgC2O4 -> Mg(2+) + C2O4(2-)
    s s s
    ksp = [Mg(2+)] [C2O4(2-)]
    ksp = s . s
    ksp = s^2
    ksp = (9,3 . 10^-3)^2
    ksp = 8,469 . 10^-5

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