1. G(x) = 2x / x + 5; x ≠ -3. Invers fungsi G(x)? 2. F(x) = 5x - 3, G(x) = 3x + b, dan f (G {0}) = 1, maka nilai G(2)? 3. (H∧-1 0 G∧-1 0 f∧-1) (x) = x-2 / 2 dan
Matematika
RM273
Pertanyaan
1. G(x) = 2x / x + 5; x ≠ -3. Invers fungsi G(x)?
2. F(x) = 5x - 3, G(x) = 3x + b, dan f (G {0}) = 1, maka nilai G(2)?
3. (H∧-1 0 G∧-1 0 f∧-1) (x) = x-2 / 2 dan (F {0G}) (x) = 2x + 5. Inlaid dari h (1)?
2. F(x) = 5x - 3, G(x) = 3x + b, dan f (G {0}) = 1, maka nilai G(2)?
3. (H∧-1 0 G∧-1 0 f∧-1) (x) = x-2 / 2 dan (F {0G}) (x) = 2x + 5. Inlaid dari h (1)?
1 Jawaban
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1. Jawaban 4LL
Langsung aja y
nomor 1 dan 2 aja y kak, nomor 3 gak paham
1.
g(x) = 2x / (x+5)
y = 2x / (x+5)
y(x+5) = 2x
xy + 5y = 2x
2x - xy = 5y
x(2-y) = 5y
x = 5y / (2-y)
g`¹(x) = 5x / (2-x)
2.
f{g(0)} = 5{g(0)} - 3
1 = 5{3(0) + b} - 3
1 = 5(0+b) - 3
1 = 0 + 5b - 3
5b = 4
b = 4/5
g(x) = 3x + b
g(x) = 3x + 4/5
g(2) = 3(2) + 4/5
g(2) = 6 + 4/5
g(2) = 30/5 + 4/5
g(2) = 34/5
semoga berguna +_+