No. 21 yaaaa thanks before
Matematika
CCC221
Pertanyaan
No. 21 yaaaa
thanks before
thanks before
1 Jawaban
-
1. Jawaban whongaliem
ma = 2 ; a ⊥ b ⇒ ma x mb = - 1
2 x mb = - 1
mb = - 1/2
grs b melalui titik (0 , 2)
pers grs b : y - yb = mb (x - xb)
y - 2 = - 1/2 (x - 0)
y - 2 = - 1/2 x .... kalikan dengan 2
2y - 4 = - x
titik potong grs b pada sumbu x ⇒ y = 0
2y - 4 = - x
2 (0) - 4 = - x
- 4 = - x
x = 4 ===> titik potong ( 4 , 0)
grs c // a ⇒ mc = ma = 2 dan melalui titik (4 , 0)
pers grs c :
y - yc = mc (x - xc)
y - 0 = 2 (x - 4)
y = 2x - 8
y - 2x + 8 = 0 ..... jawaban : C