Matematika

Pertanyaan

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1 Jawaban

  • Besar ∠BDC
    = 180 - (8x - 11)
    = 180 - 8x + 11
    = (191 - 8x)°

    Besar ∠CBD
    = 180 - 38 - (191 - 8x)
    = 180 - 38 - 191 + 8x
    = (-49 + 8x)°

    ∠ABD + ∠CBD = 180 (berpelurus)
    (9x + 25) + (-49 + 8x) = 180
    9x + 25 - 49 + 8x = 180
    17x - 24 = 180
    17x = 204
    x = 204/17
    x = 12°

    Besar ∠CBD
    = -49 + 8x
    = -49 + 8 (12)
    = -49 + 96
    = 47°

    atau

    Besar ∠CBD
    = 180 - (9x + 25)
    = 180 - 9x - 25
    = -9x + 155
    = -9 (12) + 155
    = -108 + 155
    = 47°