Matematika

Pertanyaan

jumlah 10 suku deret 2+4+8+16+...adalah...

2 Jawaban

  • sn = a(1 - r*n) / 1 - r
    a = 2, r = 2

    s10 = 2(1 - 2*10) / 1-2
    s10 = 2(1023) / -1
    s10 = 2 x 1023 / -1
    s10 = -2046
  • u1=2
    u2=4

    s10=....?

    a.r^n-1/a.r^n-1 = 8/4
    r^2= 4
    r=2

    s10= a(r^n - 1) / r^n- 1
    = 2(2^10-1) /2-1
    =2 (1023)
    =2046

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