² ㏒ (x-1) + ² ㏒ (5-x) - ² ㏒ x-2) = 3 Tentukan nilai x!

²log[(x - 1)(5 - x)/(x - 2)] = ²log8
(x - 1)(5 - x)/(x - 2) = 8
(x - 1)(5 - x) = 8(x - 2)
5x - x² - 5 + x = 8x - 16
x² + 2x - 11 = 0, misal dg melengkapkan kuadrat
x² + 2x = 11
x² + 2x + 1² = 11 + 1²
(x + 1)² = 12
x + 1 = ±√12
maka yg memenuhi
x = -1 ± 2√3