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Bantu yah nmr 3 Nya
Please..........
Bantu yah nmr 3 Nya Please..........

1 Jawaban

  • F cos teta - f = m x a
    vt^2 = vo^2 + 2as
    2^2 = 0^2 +2(5)a
    10a = 4
    a = 4/10 = 0,4 m/s2

    Fcos 30 - (ux m x g) = m xa
    F 1/2 akar3 - (0,1×15×9,8) = 15 ×0,4
    F1/2 akar3 - 14,7 = 6
    F1/2 akar3 = 20,7
    F = 20,7×2/akar3
    F = 23,54 N